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c_{v}路=路\frac{U路\cdot路I路\cdot路t}{m路\cdot路\Delta路
T}=\frac{4.95路\cdot路2.42路\cdot路180}{0.15652路\cdot路
2.7}=5102.2...路\approx路5.10路\cdot路10^3路\,路J/KgK露
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c_{v} = \frac{U \cdot I \cdot t}{m \cdot \Delta T}=\frac{4.95 \cdot 2.42 \cdot 180}{0.15652 \cdot 2.7}=5102.2... \approx 5.10 \cdot 10^3 \, J/KgK
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Author: Edvin Lindkvist 387