$${\overline {\mathrm {Nu} }}_{D}\ =0.3+{\frac {0.62\mathrm {Re} _{D}^{1/2}\Pr ^{1/3}}{\left[1+(0.4/\Pr )^{2/3}\,\right]^{1/4}\,}}{\bigg [}1+{\bigg (}{\frac {\mathrm {Re} _{D}}{282000}}{\bigg )}^{5/8}{\bigg ]}^{4/5}\quad \Pr \mathrm {Re} _{D}\geq 0.2$$