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\left(\betamc^{2}+c\left(\sum_{n{\mathop
{=}}1}^{3}\alpha_{n}p_{n}\right)\right)\psi(x,t)=i\hbar
{\frac{\partial\psi(x,t)}{\partialt}}
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\left(\beta mc^{2}+c\left(\sum _{n{\mathop {=}}1}^{3}\alpha _{n}p_{n}\right)\right)\psi (x,t)=i\hbar {\frac {\partial \psi (x,t)}{\partial t}}