Loading [MathJax]/extensions/MathMenu.js
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\begin{tikzpicture}卢
\tkzTabInit[lgt=4,espcl=3]{$n$路/1,路$2n^2-2n+4$路/1,路
$4n(n-1)$路/1,路$\dfrac{2n^2-2n+4}{4n(n-1)}$路
/2}{$0$,$1$,$+\infty$}卢
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Author: Anonymous User 361